A diffraction grating gives a second-order maximum at as angle of 31‹ for violet light (ƒÉ = 4.0 ~ 102 nm). If the diffraction grating is 1.0 cm in width, how many lines are on this diffraction grating?

Question

A diffraction grating gives a second-order maximum at as angle of 31‹ for violet light (ƒÉ = 4.0 ~ 102 nm).  If the diffraction grating is 1.0 cm in width, how many lines are on this diffraction grating?

Rach · Answer

Sorry about the double post, and
the question is:
A diffraction grating gives a second-order maximum at as angle of 31 degrees for violet light (wavelength = 4.0 x 102 nm). If the diffraction grating is 1.0 cm in width, how many lines are on this diffraction grating?

bobpursley · Answer

n lambda = d sin( theta ) d=n * lambda/sinTheta solve for d. That is the distance between slits, so lines/distance= 1/d change wavelength to cm if you want lines per cm

Rach · Answer

isn't that derived from the formula used for single slit though? and this is multiple slit (isn't that the same eqns as double slit?

Rach · Answer

so n= 2 (second order) theta= 31 degrees d= 0.1 m lambda= 4.0 x 10^-7 m (i'm required to solve in m) is this correct?

Anonymous · Answer

no

A diffraction grating gives a second-order maximum at as angle of 31�‹ for violet light (ƒÉ = 4.0 �~ 102 nm). If the diffraction grating is 1.0 cm in width, how many lines are on this diffraction grating?