A diameter of a circle has endpoints P(-10,2) and Q(4,6)

Question

a. find the center of the circle.
b. find the radius of your answer is not an interger express in radical form
c. write an equation for the circle

Answer 1

The center is the midpoint of PQ: (-3,4)
The radius is half the length of PQ: 1/2 √(14^2+4^2)

Now, knowing the center and the radius, you know that the equation is

(x+3)^2 + (y-4)^2 = r^2

Answer 2

i got (x+3)^2 + (y-2)^2=65

Please help