To find the surface area of the outer part of the hourglass sculpture, we need to calculate the surface area of the two cones that form the hourglass.
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Find the radius of the base of the cones: The diameter of each cone is 8 feet, thus the radius \( r \) is: \[ r = \frac{diameter}{2} = \frac{8}{2} = 4 \text{ feet} \]
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Find the slant height (\( l \)) of each cone: Given that the slant height \( l \) is 5 feet.
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Calculate the lateral surface area of one cone: The formula for the lateral surface area \( A \) of a cone is: \[ A = \pi r l \] Substituting the values: \[ A = 3.14 \times 4 \times 5 = 3.14 \times 20 = 62.8 \text{ square feet} \]
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Calculate the total surface area for the two cones: Since there are two identical cones in the hourglass, the total surface area \( A_{total} \) is: \[ A_{total} = 2 \times A = 2 \times 62.8 = 125.6 \text{ square feet} \]
However, we note that in the hourglass sculpture, the bases of the cones are not part of the outer surface area since they are meeting at the top point. Therefore, we are only concerned with the lateral surface area of the two cones, which would indeed be 125.6 square feet.
None of the responses given (113.04, 226.08, 653.12, and 326.56) directly match 125.6 square feet. Would you like to double-check the numbers or clarify any specific conditions?