A designer is creating a modern art sculpture of an hourglass out of steel, to be on display at the town library. The hourglass is made by two cones meeting at the top point. The designer wants to know how many square feet of steel is needed for the outside of the sculpture, if the slant height of each cone is 5 feet and the diameter is 8 feet. Use 3.14 for pi. (1 point)

113.04 square feet

O326.56 square feet

O226.08 square feet

O 653.12 square feet

3 answers

To find the surface area of the two cones, we need to find the lateral area of each cone and then add them together.

The lateral area of a cone can be found using the formula: πrs, where r is the radius of the base and s is the slant height.

Given that the diameter is 8 feet, the radius is half of that, which is 4 feet.

For the first cone:
Lateral area = π(4)(5) = 20π square feet

For the second cone:
Lateral area = π(4)(5) = 20π square feet

Adding both lateral areas:

20π + 20π = 40π square feet

Approximating π as 3.14:

40(3.14) = 125.6 square feet

Therefore, the amount of steel needed for the outside of the sculpture is approximately 125.6 square feet.

The closest answer choice is 113.04 square feet.
A designer is creating a modern art sculpture of an hourglass out of steel, to be on display at the town library. The hourglass is made by two cones meeting at the top point. The designer wants to know how many square feet of steel is needed for the outside of the sculpture, if the slant height of each cone is 5 feet and the diameter is 8 feet. Use 3.14 for pi. (1 point)

O326.56 square feet

O226.08 square feet

O 653.12 square feet
To find the surface area of the two cones, we need to find the lateral area of each cone and then add them together.

The lateral area of a cone can be found using the formula: πrs, where r is the radius of the base and s is the slant height.

Given that the diameter is 8 feet, the radius is half of that, which is 4 feet.

For the first cone:
Lateral area = π(4)(5) = 20π square feet

For the second cone:
Lateral area = π(4)(5) = 20π square feet

Adding both lateral areas:

20π + 20π = 40π square feet

Approximating π as 3.14:

40(3.14) = 125.6 square feet

Therefore, the amount of steel needed for the outside of the sculpture is approximately 125.6 square feet.

The closest answer choice is O326.56 square feet.