a delivery person pulls a 20.8 kg box across the floor. the force exerted on the box is 95.6n (35 above the horizontal). the force of kinetic friction on the box has a magnitude of 75.5n. the box starts from rest. using the work-energy theorem determine the speed of the box after being dragged 0.750m.

1 answer

work done by person ... 95.6 N * cos(35ยบ) * .750 m

work done by friction ... 75.5 N * .750 m

the difference in the two work amounts is the kinetic energy of the box

K.E. = 1/2 * mass * speed^2