A defibrillator is used during a heart attack to restore the heart to its normal beating pattern. A defibrillator passes 18 A of current

through the torso of a person in 2.0 ms.

a) How much charge moves during this time?

b) How
many electrons pass through the wires connected to the patient?

4 answers

Q = I*t, which means
(charge,coulombs)
= [current,amps)*(time,seconds)

Divide the Charge Q by the electron charge, e, to get the number of electrons.

Look up the electron charge if you don't know it. It is a number you should memorize. You should also memorize the formula.
122
a) 0.036 C

b) 2.25E17
in the mean time (nine) minus (one) (eight)
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