A deer runs into the road 1.24 km in front of a car. The driver, traveling at 70.5 km/hr, sees the deer and slams on the brakes which decelerates the car at a rate of 3.2 x 10-1 m/s2. Will the driver hit the deer?

Answer 1

Vo = 70.5km/h = 70,500m/3600s = 19.6 m/s.

V^2 = Vo^2 + 2a*d.
0 = 19.6^2 - 2*0.32*d, d = ?.

1.24 km = 1240 m.

The stopping distance(d) will be less than 1240 m and the driver stops before hitting the deer.