A deer population was measured to be 4000. Two years later , it was measured to be 4300. assume the population grows exponentially.

Question

A deer population was measured to be 4000. Two years later , it was measured to be 4300. assume the population grows exponentially.
A). Write an equation describe this situation. Find values of all constants.
b) What will the population be four years after the first measurement?
C).How many years will it take the population to double?

bobpursley · Answer

present=original*e^kt 4300/4000=e^k*2 ln of both sides.. 2k=.073 k=.0365 a) present=4000e^(.0365t) b. P(6)=4300e^(4*.0365)=4976 c. 2=e^((.0365t) ln2=.0365 t solve for t. I get about 19 years