how far does it fall in .19 s ?
delta h = (1/2) g t^2
= 4.9*.19^2 = .177 meter = 17.1 cm
u = 14
d = u t = 14 *.19 = 2.66 m to board
A dart is thrown horizontally with an initial speed of 14 m/s toward point P, the bull's-eye on a dart board. It hits at point Q on the rim, vertically below P, 0.19 s later. (a) What is the distance PQ? (b) How far away from the dart board is the dart released?
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