A daredevil on a motorcycle leaves the end of a ramp with a speed of 35.5 m/s as in the figure below. If his speed is 34.0 m/s when he reaches the peak of the path, what is the maximum height that he reaches? Ignore friction and air resistance.

m

1 answer

since speed at the top is all horizontal, we know that

35.5 cosθ = 34

Now you can figure the vertical speed at takeoff, so use what you know about max height given initial vertical speed.