A daredevil is shot out of canon at 40°above the horizontal with a speed of 25.0 m/s. If the net is located 2.00 m higher than the launch point, what is the horizontal distance to the net if it is to safely catch the daredevil?

Answer 1

time in air:
hf=hi+V*sinTheta*t-1/2 g t^2
hi=0, solve for time t. Use the quadratic equaiton.

Now with time t,
hordistance=V*cosTheta*t

Answer 2

65m?