A cylindrical tin full of engine oil has a diameter of 12cm and a height of 14cm. The oil is poured into a rectangular tin 16cm long and 11cm wide. What is the depth of the oil in the tin?

Question

A cylindrical tin full of engine oil has a diameter of 12cm and  a height of 14cm.  The oil is poured into a rectangular tin 16cm long and 11cm wide. What is the depth of the oil in the tin?

R_scott · Accepted Answer

the volumes are equal π * (12/2)^2 * 14 = d * 16 * 11

oobleck · Answer

The volume doesn't change, so if the oil has depth h, then 16*11*h = π*6^2*14

Success · Answer

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Brianna · Answer

I don't understand

David · Answer

Home work

Temilola · Answer

I don't understand what is the real answer to the question

Toyinbo Oyinkansola · Answer

I don't understand

Moses · Answer

I can't find the answer to the question

Jay · Answer

what's the answer

Marynet · Answer

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Tariro makumbe · Answer

Volume of cylinder=πr2h 22÷7 ×(6)2×14 22×36×2 1584cmcubic Area of rectangle=l ×w 16cm×11cm 176cmsquare

Bot · Answer

Since the volume of the cylinder and the volume of the rectangular tin are the same, we can equate them.

Volume of cylinder = volume of rectangular tin

π(6)^2(14) = 16(11)d

Simplifying this expression gives:

π(6)^2(14)/16(11) = d

d ≈ 5.44 cm

Therefore, the depth of the oil in the rectangular tin is approximately 5.44 cm.