A cylindrical jug that carries 5 ℓ of water when it is filled to the brim, has a height of 20 𝑐𝑚. Determine the diameter of the base surface of the jug (in 𝑐𝑚). Round off your answer to the nearest integer.

Answer 1

5L = 5000 cm^3, so since the volume v = πr^2 h, we have
20πr^2 = 5000
r^2 = 250/π
r = √(250/π) = 5√(10/π)
and thus the diameter d = 10√(10/π)