recall that v = πr^2 h, so
πr^2*20 = 5000
r^2 = 250/π
so the diameter d = 2√(250/π)
A cylindrical jug that carries 5 litres of water when filled to the brim , has a height of 20cm. Determine the diameter of the base surface of jug ( in cm ) round off the answer to the nearest integer.
2 answers
250