Cost=.10*(pi*r^2+2Pi*r*h)+.20PIr^2
volume= PIr^2h or h= volume/PIr^2
h=3000/(PIr^2)
Put that into the cost function for h.
Then take the derivative of cost with respect to r (dCost/dr), set equal to zero, solve for r.
A cylindrical container with a volume of 3000 cm^3 is constructed from two types of material. The side and bottom of the container cost $0.10/cm^2 and the top of the container costs $0.20/cm^2.
a) Determine the radius and height that will minimize the cost.
b) Determine the ratio of diameter to height.
Could you please help me with these questions please and thank you
2 answers
lol i need help on the same one