A cylindrical container 1.5m tall contains mercury to a certain depth, d. The rest of the cylinder is filled with water. If the pressure at the bottom of the cylinder is two atmospheres, what is the depth d?
I used this equation: 2atm = 1atm + (density of water* gravity* height of water) + (density of mercury*gravity*height of mercury)
where height of mercury = the depth d
and height of water = 1.5m - d
I used 13.534g/ml^3 and converted into kg/ml for the density of mercury and 1000g/ml for the density of water. My anwer was 1.4m but that is not right.
I tried solving this question with equation from similar questions that were answered here but didn't get the answer right. Can I get some help please?