to maintain the volumetric flow rate
... the blood must go faster in a narrower vessel
v = v0 * √(1 / .520)
A cylindrical blood vessel is partially blocked by the buildup of plaque. At one point, the plaque decreases the diameter of the vessel by 52.0%. The blood approaching the blocked portion has speed v0. Just as the blood enters the blocked portion of the vessel, what is its speed v, expressed as a multiple of v0?
2 answers
oops ...
v = v0 * √(1 - .520)
v = v0 * √(1 - .520)
1 answer