To find the area of the ring formed by slicing the region outside the cone, we need to find the difference in areas of two circles.
The outer circle is formed by slicing the cylinder, which has a radius of 8 cm. The inner circle is formed by slicing the cone, which also has a radius of 8 cm.
The formula for the area of a circle is A = πr^2, where A is the area and r is the radius.
So, the area of the outer circle is A1 = π(8^2) = 64π cm^2.
The area of the inner circle is A2 = π(8^2) = 64π cm^2.
The area of the ring is the difference between the two areas, A_ring = A1 - A2 = 64π - 64π = 0 cm^2.
Therefore, the area of the ring is 0 cm^2.
To prove that the disk formed by slicing the hemisphere has the same area as the ring, we need to find the area of the disk.
The radius of the hemisphere is also 8 cm, so the area of the disk is A_disk = π(8^2) = 64π cm^2.
Therefore, the area of the disk is 64π cm^2.
Since the area of the ring is 0 cm^2 and the area of the disk is 64π cm^2, we can conclude that the disk has the same area as the ring.
A cylinder rests on top of a table, with a cone inscribed within, vertex up. Both heights and radii are 8 cm. A hemispherical bowl of radius 8 cm rests nearby on the same table, its circular rim parallel to the table. Consider that part of the cylinder that is outside (above) the cone. Slice this region by a plane that is parallel to the table and 3 cm from it. The intersection is a ring between two concentric circles. Calculate its area. The same plane slices the hemisphere, creating a disk. Show that the disk has the same area as the ring. The diagram shows both a top view and a side view of the ring, the disk, and the hemisphere. Note that point B is on the table.
5 answers
A cylinder rests on top of a table, with a cone inscribed within, vertex up. Both heights and radii are 8 cm. A hemispherical bowl of radius 8 cm rests nearby on the same table, its circular rim parallel to the table. Consider that part of the cylinder that is outside (above) the cone. Slice this region by a plane that is parallel to the table and 3 cm from it. The intersection is a ring between two concentric circles. The area of the ring is 122.521 cm^2. The same plane slices the hemisphere, creating a disk. Show that the disk has the same area as the ring. The diagram shows both a top view and a side view of the ring, the disk, and the hemisphere. Note that point B is on the table.
To show that the disk formed by slicing the hemisphere has the same area as the given ring, we need to compare their areas.
Let's find the area of the ring first. Given that the area of the ring is 122.521 cm^2, we denote it as A_ring = 122.521 cm^2.
Now, let's find the area of the disk formed by slicing the hemisphere. To do this, we need to calculate the radius of the disk.
Consider the side view of the ring, disk, and hemisphere. We can see that the distance between the center of the hemisphere and the plane is the sum of the height of the cylinder (8 cm) and the distance of the plane from the table (3 cm), which gives us a total distance of 11 cm.
According to the given information, the radius of the hemisphere is 8 cm. Therefore, the radius of the disk formed by slicing the hemisphere is 8 - 11 = -3 cm. However, the radius cannot be negative in this context, so we take the absolute value, which gives us a radius of 3 cm.
Now, we can find the area of the disk. The formula for the area of a disk is A = πr^2, where A is the area and r is the radius.
Substituting the radius into the formula, we have A_disk = π(3^2) = 9π cm^2.
Therefore, the area of the disk is 9π cm^2.
Comparing the areas, we have A_ring = 122.521 cm^2 and A_disk = 9π cm^2.
To verify that the disk has the same area as the ring, we need to check if A_disk = A_ring.
Converting the value of π to decimal approximation, we find that π is approximately equal to 3.14159.
Thus, A_disk ≈ 9(3.14159) = 28.274 cm^2.
Since 28.274 cm^2 is not equal to 122.521 cm^2, the disk does not have the same area as the ring.
Therefore, there may be an error in the calculations or an incorrect assumption made. Please verify the given information and recalculate accordingly.
Let's find the area of the ring first. Given that the area of the ring is 122.521 cm^2, we denote it as A_ring = 122.521 cm^2.
Now, let's find the area of the disk formed by slicing the hemisphere. To do this, we need to calculate the radius of the disk.
Consider the side view of the ring, disk, and hemisphere. We can see that the distance between the center of the hemisphere and the plane is the sum of the height of the cylinder (8 cm) and the distance of the plane from the table (3 cm), which gives us a total distance of 11 cm.
According to the given information, the radius of the hemisphere is 8 cm. Therefore, the radius of the disk formed by slicing the hemisphere is 8 - 11 = -3 cm. However, the radius cannot be negative in this context, so we take the absolute value, which gives us a radius of 3 cm.
Now, we can find the area of the disk. The formula for the area of a disk is A = πr^2, where A is the area and r is the radius.
Substituting the radius into the formula, we have A_disk = π(3^2) = 9π cm^2.
Therefore, the area of the disk is 9π cm^2.
Comparing the areas, we have A_ring = 122.521 cm^2 and A_disk = 9π cm^2.
To verify that the disk has the same area as the ring, we need to check if A_disk = A_ring.
Converting the value of π to decimal approximation, we find that π is approximately equal to 3.14159.
Thus, A_disk ≈ 9(3.14159) = 28.274 cm^2.
Since 28.274 cm^2 is not equal to 122.521 cm^2, the disk does not have the same area as the ring.
Therefore, there may be an error in the calculations or an incorrect assumption made. Please verify the given information and recalculate accordingly.
A cylinder rests on top of a table, with a cone inscribed within, vertex up. Both heights and radii are 8 cm. A hemispherical bowl of radius 8 cm rests nearby on the same table, its circular rim parallel to the table. Consider that part of the cylinder that is outside (above) the cone. Slice this region by a plane that is parallel to the table and 3 cm from it. The intersection is a ring between two concentric circles. The area of the ring is 122.521 cm^2. The same plane slices the hemisphere, creating a disk. Show that the disk has the same area as the ring.
To show that the disk formed by slicing the hemisphere has the same area as the given ring, we need to compare their areas.
Given that the area of the ring is 122.521 cm^2, we denote it as A_ring = 122.521 cm^2.
Now, let's find the area of the disk formed by slicing the hemisphere. To do this, we need to calculate the radius of the disk.
Consider the side view of the ring, disk, and hemisphere. We can see that the distance between the center of the hemisphere and the plane is the sum of the height of the cylinder (8 cm) and the distance of the plane from the table (3 cm), which gives us a total distance of 11 cm.
According to the given information, the radius of the hemisphere is 8 cm. Therefore, the radius of the disk formed by slicing the hemisphere is still 8 cm, as the plane is parallel to the table and does not change the radius.
Now, we can find the area of the disk. The formula for the area of a disk is A = πr^2, where A is the area and r is the radius.
Substituting the radius into the formula, we have A_disk = π(8^2) = 64π cm^2.
To compare the areas, we need to approximate the value of π. Using 3.14159 as an approximation, we have A_disk ≈ 64(3.14159) ≈ 201.062 cm^2.
Therefore, the area of the disk is approximately 201.062 cm^2.
Comparing the areas, we have A_ring = 122.521 cm^2 and A_disk ≈ 201.062 cm^2.
Since 122.521 cm^2 is not equal to 201.062 cm^2, the disk does not have the same area as the ring.
Therefore, there may be an error in the calculations or an incorrect assumption made. Please verify the given information and recalculate accordingly.
Given that the area of the ring is 122.521 cm^2, we denote it as A_ring = 122.521 cm^2.
Now, let's find the area of the disk formed by slicing the hemisphere. To do this, we need to calculate the radius of the disk.
Consider the side view of the ring, disk, and hemisphere. We can see that the distance between the center of the hemisphere and the plane is the sum of the height of the cylinder (8 cm) and the distance of the plane from the table (3 cm), which gives us a total distance of 11 cm.
According to the given information, the radius of the hemisphere is 8 cm. Therefore, the radius of the disk formed by slicing the hemisphere is still 8 cm, as the plane is parallel to the table and does not change the radius.
Now, we can find the area of the disk. The formula for the area of a disk is A = πr^2, where A is the area and r is the radius.
Substituting the radius into the formula, we have A_disk = π(8^2) = 64π cm^2.
To compare the areas, we need to approximate the value of π. Using 3.14159 as an approximation, we have A_disk ≈ 64(3.14159) ≈ 201.062 cm^2.
Therefore, the area of the disk is approximately 201.062 cm^2.
Comparing the areas, we have A_ring = 122.521 cm^2 and A_disk ≈ 201.062 cm^2.
Since 122.521 cm^2 is not equal to 201.062 cm^2, the disk does not have the same area as the ring.
Therefore, there may be an error in the calculations or an incorrect assumption made. Please verify the given information and recalculate accordingly.
1 answer