A cyclist rode her bicycle 10 1/2 miles on Monday, 12 7/8 miles on Tuesday, and 11 4/5 miles on Wednesday. Compute the total distance for the three days.

Question

Group of answer choices

35 9/40 miles

35 7/40 miles

24 7/40 miles

34 7/40 miles

Answer 1

To solve this problem, first, find the sum of the three distances:

10 1/2 + 12 7/8 + 11 4/5

To add the fractions, find a common denominator:

10 1/2 + 12 7/8 + 11 4/5 = 10 4/8 + 12 7/8 + 11 4/5

Convert each fraction to an equivalent fraction with a denominator of 40:

10 4/8 = 10 20/40

12 7/8 = 12 35/40

11 4/5 = 11 32/40

Now add the numbers and fractions separately:

10 + 12 + 11 = 33

20/40 + 35/40 + 32/40 = 87/40

Combine the whole number and fraction:

33 + 87/40

To add a whole number and a fraction, convert the whole number to a fraction with a denominator of 40:

33 = 1320/40

1320/40 + 87/40 = 1407/40

Divide the numerator by the denominator to simplify:

1407 ÷ 40 = 35 remainder 7

The final answer is:

35 7/40 miles

Therefore, the total distance for the three days is 35 7/40 miles.