Asked by Tenshi
A curve passes through the point (0, 2) and has the property that
the slope of the curve at every point P is three times the y-coordinate
of P. Find an equation of the curve.
dy/dp = 3y
or ∫ (3/y) dy = ∫ dp
or 3 ln(y) = p + c
or @ (0,2)
ln(2) = 0 + c
or c = ln(2)
3 ln(y) = p + ln(2)
or y = e^( (p + ln(2)) ^(1/3) )
the slope of the curve at every point P is three times the y-coordinate
of P. Find an equation of the curve.
dy/dp = 3y
or ∫ (3/y) dy = ∫ dp
or 3 ln(y) = p + c
or @ (0,2)
ln(2) = 0 + c
or c = ln(2)
3 ln(y) = p + ln(2)
or y = e^( (p + ln(2)) ^(1/3) )
Answers
Answered by
Steve
Odd notation. P is a point (x,y) so usually we would see
dy/dx = 3y
y = c*e^3x
2 = c, so
y = 2e^(3x)
You divided the right side by 3 and multiplied the left aside by 3, but that was not correct:
dy/dp = 3y
∫dy/y = ∫3dp
...
dy/dx = 3y
y = c*e^3x
2 = c, so
y = 2e^(3x)
You divided the right side by 3 and multiplied the left aside by 3, but that was not correct:
dy/dp = 3y
∫dy/y = ∫3dp
...
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