Formula: tanØ=v^2/gr
Given:
radius=50m
Velocity=15m/s
Required:Ø
Solution:
tanØ= (15m/s)^2/ (9.8m/s)(50m)
Ø= arctan(15m/s)^2/(9.8m/s)(50m)
Ø=arctan(45/98)
Ø=24°40"
a curve of radius 50 m is to be banked, so that the automobile may make a turn at a speed of 15 m/s without depending on friction. at what angle should the road be banked?
1 answer