slope of the given line is -3/2
so x^2 - 1 must be equal to -3/2
x^2 - 1 = -3/2
x^2 = 1 - 3/2 = -1/2
BUT a square of a real number cannot be negative, so no solution,
so no such tangent
a curve is such that dy/dx = x^2 - 1
Show that no tagent to this curve is parallel to the line with equation
3x + 2y - 4 = 0
1 answer
1 answer