coulombs = amperes x seconds or
coulombs = 45 x 1.75 hrs x (60 min/hr) x (60 sec/min) = 283,500
96,485 coulombs will deposit about 197/3 g Au But you can use closer numbers than that.
So g Au deposited = (197/3) x (283,500/96,485) = ? g Au.
I suppose part b is mols and not mass so g Au/molar mass = mols Au.
C. Follow the steps in part A to do C and find the time.
Post your work if you get stuck.
A current of 45A is passing through a solution of gold salt for 1:45 minutes
a)calculate the mass of AU deposited
b )number of mass deposited
c) if the same current is use find the time taken for 5.5 g of the AU deposited
4 answers
Please where did you get the 96,485 from.
How is it 96485 and where did the 197/3 come from
what the correct answer?
3 answers