A current of 3.04 A is passed through a Cr(NO3)2 solution for 1.80 hours. How much chromium is plated out of the solution?

Answer 1

Coulombs = amperes x seconds
C = 3.04 x 1.80 hr x (60 min/hr) x (60sec/min) = estimated 20,000
96,485 C will deposit 52/3 g Cr or estimated 17 g Cr.
17 g x (20,000/96,485) = g Cr deposited.

Answer 2

How did you get 52/3??