A current of 20 mA flows in a single circular loop with a radius of 2 meters. A uniform magnetic field of 1.2 T points parallel to the plane of the loop. What is the magnitude of the magnetic moment of the loop in A-m^2?

Question

What is the magnitude of the torque on the loop in N-m?

Answer 1

A current of 20 mA flows in a single circular loop with a radius of 2 meters. A uniform magnetic field of 1.2 T points parallel to the plane of the loop. What is the magnitude of the magnetic moment of the loop in A-m^2?

What is the magnitude of the torque on the loop in N-m?

Answer 2

magnetic moment= current(I)* area(A)
= 20*10^-3* pi*2^2
= 0.2513

torque= magnetic moment*magnetic field(B)
= 0.2513*1.2
=0.301