The capacitance C of that capacitor is
C = epsilon*A/d
Also, the charge on the plates is
Q = CV
dQ/dt = I = C dV/dt = (C*d)dE/dt
= epsilon*A*dE/dt
where epsilon is the permittivity of the speace between the plates. d, the dap between the plates, cancels out. Solve for dE/dt.
Use Ampere's law to answer your second question. The line integral of B is proportional to the current I through the loop and a permeability constant, mu
a current of 10A flows into a parallel plate capacitor with square plates with area .5m^2
how do you find the dE/dt between the plates?
what is the line integral B.dl around a circular closed contour with a diameter of 10cm perpendicular to the electric field?
1 answer
1 answer