A cubical object of sides 5 cm is immersed completely in water. What is the force of buoyancy on the object? (Assume g = 10 m/s2)

Answer 1

.05 m on a side
volume = .05^3 = 125 * 10^-6 m^3

mass of water displaced = 10^3 kg/m^3 * 125*10^-6 m^3 = .125 kg
Archimedes says force up = weight of water displaced
g = 10 m/s^2
so
m g = 1.25 Newtons

Answer 2

Thanks!!

Answer 3

You are welcome.