A cubical metal box has side L=10.34cm and mass m=150 g. How much mass must be placed inside the box if it is to float in water with its top at the surface?

Answer 1

volume of water displaced = .1034^3 = .0011055 m^3
times density of water which is about 1000 kg/m^3
=1.106 kg of water displaced
Archimedes says we can float that much mass
.150 + m = 1.106
m = .956 kg = 956 grams