Fg/Fb=p(row)(object)/p(fluid)
9.81/Fb=.78/1
=7.65 N
A cube of wood with a density of 0.780 g/cm3 is 10.0 cm on each side. When the cube is placed in water, what buoyant force acts on the wood? (ρw = 1.00 g/cm3)
a. 5.00 N
b. 6.40 N
c. 7.65 N
d. 7.65 x 10^3 N
2 answers
Ben's answer is wrong. He had to cross multiply and then divide but he just straight up multiplied Fg and po