A cube of length 2.5 cm is placed in a uniform magnetic field of B= (5i+4j+3k)T calculate the flux through the shaded face of the cube

1 answer

The flux through a surface is given by the dot product of the magnetic field vector and the normal vector to the surface, multiplied by the area of the surface.

The shaded face of the cube is one of the faces with dimensions 2.5 cm x 2.5 cm = 6.25 cm² = 6.25 x 10^-4 m².

The normal vector to the shaded face is in the negative z-direction, so it is -k.

Taking the dot product of the magnetic field vector and the normal vector:
B = (5i + 4j + 3k) T
n = -k
B.n = (5i + 4j + 3k) . (-k) = 3

Therefore, the flux through the shaded face of the cube is:
Flux = B.n * A = 3 * 6.25 x 10^-4 = 1.875 x 10^-3 Wb or Tesla meter².