A cube of ice is take from the freezer at -8.5C and placed in a 95g calorimeter aluminum cup containing 310g of water at 20degC. The final situation is observed to be all water at 17degC. What was the mass of the ice cube?

Answer 1

The sum of heats gained is zero.

HeatgainedbyicewarmigtoOC + heatgainedmeltingIcd+ heat gained by aluminum+heat gained by original water=0

massice*Cice*(0-8.5C)+massice*Hf+95*Calum*(17-20)+310*Cwater*(17-20)=0
solve for mass of ice.

Answer 2

19.276g

Answer 3

m cice �
0 − (−8.5)�
| {z }
ice from −8.5
◦C to 0◦C
+ m Lwater
| {z }
ice melts at 0◦C
+ m cwater
17 − 0
�
| {z }
water from 0◦C to 17◦C
= 0.300cwater
20 − 17�
| {z }
water from 20◦C to 17◦C
+ 0.075cAl
20 − 17�
| {z }
Al from 20◦C to 17◦C
⇒ m
�
2090�
8.5 + m
�
3.33 × 105
�
+ m
�
4186�
17 = 0.300 �
4186�
3 + 0.075 �
900�
3
⇒ m
�
421,927�
= 3969.9