A cube of gold weighing 192.4g is heated from 30.0°C to some higher temperature, with the absorption of 226 joules of heat. The specific heat of gold is 0.030 J/g∙°C. What was the final temperature of the gold?

Answer 1

The specific heat formula is given as:

Q = mcΔT

where:
Q = heat energy absorbed by the object (in joules)
m = mass of the object (in grams)
c = specific heat capacity of the object (in J/g∙°C)
ΔT = change in temperature (in °C)

Given:
Q = 226 J
m = 192.4 g
c = 0.030 J/g∙°C

Let's first calculate the change in temperature using the formula:

ΔT = Q / (mc)

ΔT = 226 J / (192.4 g * 0.030 J/g∙°C)
ΔT = 226 J / 5.772 g∙°C
ΔT ≈ 39.162 °C

Now, let's find the final temperature by adding the change in temperature to the initial temperature (30.0°C):

Final Temperature = Initial Temperature + ΔT
Final Temperature = 30.0°C + 39.162 °C
Final Temperature ≈ 69.162 °C

Therefore, the final temperature of the gold cube is approximately 69.162 °C.