A cube of balsa wood (side length = 0.25 m) is tied with a string to the bottom of a waterfilled

container. The wood is completely immersed. What is the tension in the string?

1 answer

T=F(buoyancy) –mg =
= ρ(water)Vg - ρ(balsa)Vg=
=Vg[ρ(water) - ρ(balsa)] =
=0.25³•9.8(1000 – 160)=129 N