A crate with mass 32.5 kg initially at rest on a warehouse floor is acted on by a net horizontal force of 140 . How far does the crate travel in 10.0s? What is its speed at the end of 10.0s?

Answer 1

F=ma,or acceleration=force/mass

distance=1/2 a*t^2

vf=a*t

Answer 2

F=ma
a=F/m
a= 140Kg.m/s² / 32.5kg
a= 4.30769m/s²

d=Vot + 1/2at²
d=1/2at²
d=1/2(4.31m/s²)(10s)
d= 215.5m