A crate of mass 52.8 kg is being transported on the flatbed of a pickup truck. The coefficient of static friction between the crate and the trucks flatbed is 0.351, and the coefficient of kinetic friction is 0.305.

Question

(a) The truck accelerates forward on level ground. What is the maximum acceleration the truck can have so that the crate does not slide relative to the trucks flatbed?
(b) The truck barely exceeds this acceleration and then moves with constant acceleration, with the crate sliding along its bed. What is the acceleration of the crate relative to the ground?

Answer 1

(a)
ma=F(fr) = μ(s) •N= μ(s) •m•g,
a= μ(s)•g,
(b)
ma1=F1(fr) = μ(k) •N= μ(k) •m•g,
a1= μ(k)•g,

Answer 2

Can you solve so I can compare my answers to yours?

Answer 3

a= μ(s)•g= 0.351•9.8=3.44 m/s²,
a1= μ(k)•g= 0.305•9.8 =2.99 m/s²,

Answer 4

Great, that's what I had! Can you solve another problem for me?