mgh=25*15
h= 25*15/125
h= 3m
a crate is pushed to the top of a frictionless inclined plane 15 m long with a force of 25 N.
If the crate weighs 125 N, how high is the inclined plane?
0.5 m
1 m
3 m
or
5 m
3 answers
W=F(cosx)d=mgh(potential energy)
25(cos0)(15)=375
mgh=(12.77)(9.8)h
375=125h
375/125=h
h=3
25(cos0)(15)=375
mgh=(12.77)(9.8)h
375=125h
375/125=h
h=3
Work input is equal to work output (no friction)
W in = W out
F x d = F x d
25 x 15 = 125 x d
d = 3m
W in = W out
F x d = F x d
25 x 15 = 125 x d
d = 3m
1 answer