X = -116.8 + 93.5 = -23.3 N.
Y = -248.6 + 658.1 = 409.5 N.
Tan Ar = Y/X = 409.5/-23.3 = -17.57511
Ar = -86.7o = Reference angle.
A = -86.7 + 180 = 93.3o, CCW.
Fr = Y/sin A = 409.5/sin93.3 = 410 N.
[93.3o]. = Resultant force.
Fx = 410*Cos93.3 = -23.61 N = 23.61 N.,
Left(West).
A crate is pulled to the right with a force
of 93.5 N, to the left with a force of 116.8 N,
upward with a force of 658.1 N, and downward
with a force of 248.6 N.
What is the net external force in the x
direction?
Answer in units of N
1 answer