Tension force in the direction of motion = 125 cos 30
= 108 N
Work done by rope tension =
Tension force in the direction of motion times distance moved = 108*5 = 541 Joules
Since the velocity is constant, the horizontal tension force, 108 N is equal and opposite to the friction force.
Therefore if the tension force is positive, the friction force is -108 N
The crate is not accelerating.
F = m a
a is zero
therefore
the net force on the crate is zero.
A crate is dragged 5.0 along a rough floor with a constant velocity by a worker applying a force of 125N to a rope at an angle of 30degrees to the horizontal.
Calculate the work done by the tension in the rope, the force of friction, and the net force. I know the work don on the weight of the crate and the normal force is 0J. Thanks for your help, and if possible show work, thanks!
1 answer
1 answer