finish the chart
BBBB
BBBG
BBGB
BBGG
.....
GGGG --- you should have 16 of these
count the number of cases for each of your events,
then divide by 16 to the prob.
A couple intends to have four children. Assume that having a boy and girl is equally likely event.
a) List sample space
b) Find the probability that couple has two boys and two girls;
c) Find the probability that couple has at least one boy
3 answers
5. A couple plans to have 3 children. Find the possible ways the couple can have 3 children.
- 1a3b+3a2b1+3a1b2+1 a0b3
1a3= 1 case with boy, boy, boy
3a2b1= 3 cases with 2 boys and a girl
3a1b2=3 cases with a boy and 2 girls
1b3= 1 case of girl, girl and girl.
- 1a3b+3a2b1+3a1b2+1 a0b3
1a3= 1 case with boy, boy, boy
3a2b1= 3 cases with 2 boys and a girl
3a1b2=3 cases with a boy and 2 girls
1b3= 1 case of girl, girl and girl.
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