4 NDC
3 NPP
3 others
total = 10
i) one of each party:
C(4,1) x C(3,1) x C(3,1)/C(10,3)
= 36/120 = 3/10
ii) C(3,2) x (7,1)/C(10,3)
= 21/120
= 7/40
iii) follow my steps of ii)
A council consists of 10 members.four are NDC,three are NPP and three are from other parties.if a committee of three is to be selected,find the probabilities following:
I.one of each party.
II.Two NPP and one from other parties.
III.one from other parties and two NDC
(base on probability and combinatorial analysis)
1 answer