A copper complex reacts with ammonia according to the following reaction, where the left side of the reaction is a pale sky-blue color and the right side is dark blue. Cu(H2O)2+4(aq)+4NH3(aq)⇌Cu(NH3)2+4(aq)+4H2O(aq) Which change to a solution at equilibrium will make the solution darker? (1 point) Responses removing ammonia (NH3 ) removing ammonia ( NH sub 3 ) adding Cu(NH3)2+4 salt adding c u open paren n h sub 3 close paren sub 4 raised to the 2 plus power salt removing Cu(NH3)2+4 salt removing c u open paren n h sub 3 close paren sub 4 raised to the 2 plus power salt adding water (H2O ) adding water ( h sub 2 o ) Skip to navigation

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1 answer

To make the solution darker by shifting the equilibrium to the right (where the dark blue complex is formed), you should add Cu(NH3)2+4 salt. This addition increases the concentration of the products, driving the equilibrium toward the right, resulting in a darker solution.