The sum of all the heats gained is zero (some of the heats gained will be negative, as in heat lost).
Heatgainedwater+ heatgainedlead+ heatgained calorimeter+ heat gained ice=0
mw*cw*(Tf-0) + ml*cl*(Tf-255) + mc*cc*(tf-0) + massice*latentheatfusionice =0
Solve for Tf
A copper calorimeter can with mass .100 kg contains .160 kg of water and .018 kg of ice in thermal equilibrium at atmospheric pressure. If .750 kg of lead at a temperature of 255 degrees Celsius is dropped into the can what is the final temperature of the system if no heat is lost to the surroundings?
1 answer
1 answer