A copper block of mass 100g at a temperature of 150 degree celcius is dropped into a copper calorimeter of 40g containing 80g of water at 30 degree celcius. Calculate the steady final temperature of the mixture assuming no heat is lost to the surrounding.(s.h.c of copper and water are 400jkg-1k-1 and 4200jkg-1k-1)
2 answers
Pls urgent
difference in deg C is same as deg K
copper block loses = 0.100 kg * 400 (150 -T)deg C
copper pot gains 0.040 * 400 *(T- 30)
water gains 0.080 * 4200 (T-30)
so
0.1 * 400 * (150-T) = [ 0.04*400 + 0.08*4200] (T-30)
plug and chug
copper block loses = 0.100 kg * 400 (150 -T)deg C
copper pot gains 0.040 * 400 *(T- 30)
water gains 0.080 * 4200 (T-30)
so
0.1 * 400 * (150-T) = [ 0.04*400 + 0.08*4200] (T-30)
plug and chug
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