A coordinate plane with four quadrants shows x-axis ranging from negative 5 to 12 in increments of 1 and the y-axis from 17 to negative 4 in increments of 1. Points upper A, upper B, upper A prime, and upper B prime are plotted on quadrant 1. The plotted points are as follows: Upper A is left parenthesis 2 comma 3 right parenthesis and upper B is left parenthesis 4 comma 1 right parenthesis. The points are joined by a line. Upper A prime is plotted as left parenthesis 6 comma 9 right parenthesis and upper B prime as left parenthesis 12 comma 3 right parenthesis. The points are joined by a line.

Determine the scale factor used in the dilation of line segment AB, centered at the origin.

1 answer

To find the scale factor used in the dilation of line segment \(AB\), we need to compare the coordinates of points \(A\) and \(B\) with the coordinates of points \(A'\) and \(B'\).

The original points are:

  • \(A(2, 3)\)
  • \(B(4, 1)\)

The dilated points are:

  • \(A'(6, 9)\)
  • \(B'(12, 3)\)

First, we find the distances from the origin to the points \(A\) and \(A'\) and then to points \(B\) and \(B'\).

Step 1: Calculate distances from origin to points \(A\) and \(A'\)

  1. Calculate the distance \(OA\): \[ OA = \sqrt{(2-0)^2 + (3-0)^2} = \sqrt{2^2 + 3^2} = \sqrt{4 + 9} = \sqrt{13} \]

  2. Calculate the distance \(OA'\): \[ OA' = \sqrt{(6-0)^2 + (9-0)^2} = \sqrt{6^2 + 9^2} = \sqrt{36 + 81} = \sqrt{117} \]

Step 2: Calculate distances from origin to points \(B\) and \(B'\)

  1. Calculate the distance \(OB\): \[ OB = \sqrt{(4-0)^2 + (1-0)^2} = \sqrt{4^2 + 1^2} = \sqrt{16 + 1} = \sqrt{17} \]

  2. Calculate the distance \(OB'\): \[ OB' = \sqrt{(12-0)^2 + (3-0)^2} = \sqrt{12^2 + 3^2} = \sqrt{144 + 9} = \sqrt{153} \]

Step 3: Find the scale factor

The scale factor \(k\) can be calculated using the distances from the origin to the points before and after dilation.

We can find \(k\) using point \(A\): \[ k = \frac{OA'}{OA} = \frac{\sqrt{117}}{\sqrt{13}} = \sqrt{\frac{117}{13}} = \sqrt{9} = 3 \]

Now, let's verify it using point \(B\): \[ k = \frac{OB'}{OB} = \frac{\sqrt{153}}{\sqrt{17}} = \sqrt{\frac{153}{17}} = \sqrt{9} = 3 \]

Both methods yield the same scale factor, confirming the result.

Conclusion

The scale factor used in the dilation of line segment \(AB\), centered at the origin, is: \[ \boxed{3} \]