A coordinate plane with 4 quadrants shows x and y axes ranging from negative 6 to 6 in increments of 1. Three triangles are formed by joining three plotted points each. The coordinates of the plotted points for the first triangle upper A upper B upper C joined by solid lines are upper A is left parenthesis negative 4 comma 5 right parenthesis, upper B is left parenthesis negative 1 comma 3 right parenthesis, and upper C is left parenthesis negative 3 comma 1 right parenthesis. The coordinates for the second triangle upper A prime upper B prime upper C prime joined by dotted lines are as follows: upper A prime at left parenthesis 4 comma 5 right parenthesis, upper B prime at left parenthesis 1 comma 3 right parenthesis, and upper C prime at left parenthesis 3 comma 1 right parenthesis. The coordinates of the plotted points for the third triangle upper A double prime upper B double prime upper C double prime joined by lines made of dashes and dots are as follows: upper A double prime at left parenthesis 1 comma 0 right parenthesis, upper B double prime at left parenthesis negative 2 comma negative 2 right parenthesis, and upper C double prime at left parenthesis 0 comma negative 4 right parenthesis.

How would you describe this series of transformations? Reflection across the y
-axis and then a translation of (−3,−5)
shows that triangle ABC
is congruent to triangle A′′B"C"
.
Reflection across the y -axis and then a translation of left parenthesis negative 3 comma negative 5 right parenthesis shows that triangle upper A upper B upper C is congruent to triangle upper A double prime upper B double prime upper C double prime .

Rotation of 90 degrees clockwise and then reflection across the x
-axis shows that triangle ABC
is congruent to triangle A′′B"C"
.
Rotation of 90 degrees clockwise and then reflection across the x -axis shows that triangle upper A upper B upper C is congruent to triangle upper A double prime upper B double prime upper C double prime .

Translation of (2,0)
and then reflection across the x
-axis shows that triangle ABC
is congruent to triangle A′′B"C"
.
Translation of left parenthesis 2 comma 0 right parenthesis and then reflection across the x -axis shows that triangle upper A upper B upper C is congruent to triangle upper A double prime upper B double prime upper C double prime .

Since triangles ABC
and A′′B"C"
do not have the same orientation, they are not congruent..

1 answer

To analyze the transformations between the triangles \( ABC \), \( A'B'C' \), and \( A''B''C'' \), we consider their coordinates carefully.

Triangle \( ABC \):

  • \( A(-4, 5) \)
  • \( B(-1, 3) \)
  • \( C(-3, 1) \)

Triangle \( A'B'C' \):

  • \( A'(4, 5) \)
  • \( B'(1, 3) \)
  • \( C'(3, 1) \)

Triangle \( A''B''C'' \):

  • \( A''(1, 0) \)
  • \( B''(-2, -2) \)
  • \( C''(0, -4) \)

Transformation Analysis:

1. Reflecting Triangle ABC Across the Y-Axis:

The reflection of a point \( (x, y) \) across the y-axis results in \( (-x, y) \):

  • \( A \) becomes \( (4, 5) \)
  • \( B \) becomes \( (1, 3) \)
  • \( C \) becomes \( (3, 1) \)

After reflection, we observe that the new coordinates match those of triangle \( A'B'C' \).

2. Checking Orientation:

Since triangle \( ABC \) and triangle \( A'B'C' \) have the same orientation, they are congruent through the reflection across the y-axis.

3. Translation:

Next, we can describe the transformation from \( A'B'C' \) to \( A''B''C'' \).

  • The coordinates of the vertices in \( A'B'C' \) after translation of \( (-3, -5) \) will be:
    • \( A'(4, 5) + (-3, -5) = (1, 0) \) (which is \( A'' \))
    • \( B'(1, 3) + (-3, -5) = (-2, -2) \) (which is \( B'' \))
    • \( C'(3, 1) + (-3, -5) = (0, -4) \) (which is \( C'' \))

Thus, the transformation is** a reflection across the y-axis** followed by a translation of \((-3, -5)\), which confirms that triangle \( ABC \) is congruent to triangle \( A''B''C''\).

Conclusion:

In conclusion, the statement that best encapsulates these transformations is: Reflection across the y-axis and then a translation of \((-3, -5)\) shows that triangle ABC is congruent to triangle \( A''B''C'' \).

Therefore the best answer among the options provided is:

  • Reflection across the y-axis and then a translation of (-3, -5) shows that triangle ABC is congruent to triangle A''B''C''.