To determine if the points (0, -4) and (0, 2) are solutions to the given system of linear equations, we will substitute the x-coordinates of the points into both equations and see if the resulting y-values match.
The equations are:
- \(y = 2x + 2\)
- \(y = 2x - 4\)
Now, substitute \(x = 0\) into both equations:
For the point (0, -4):
-
First Equation:
\(y = 2(0) + 2 = 2\)
So, the first equation gives \(y = 2\), not -4. -
Second Equation:
\(y = 2(0) - 4 = -4\)
So, the second equation gives \(y = -4\).
The point (0, -4) satisfies the second equation but not the first equation. Thus, (0, -4) is not a solution to the system.
For the point (0, 2):
-
First Equation:
\(y = 2(0) + 2 = 2\)
So, the first equation gives \(y = 2\), which matches. -
Second Equation:
\(y = 2(0) - 4 = -4\)
So, the second equation gives \(y = -4\), which does not match.
The point (0, 2) satisfies the first equation but not the second equation. Thus, (0, 2) is not a solution to the system.
Conclusion:
Since neither (0, -4) nor (0, 2) are solutions to both equations, the correct response is:
Neither of these points are solutions.