A cooler at a soccer game holds 10 apple juices and 10 orange juices. If the first player choose juice and drinks it, then a second player chooses a juice, what is the probability that both players would choose orange juice?

Answer 1

There are 10 orange juices out of a total of 20 juices in the cooler.

Therefore, the probability that the first player chooses an orange juice is 10/20 = 0.5.

After the first player has chosen an orange juice, there are now 9 orange juices and 19 total juices left in the cooler.

Therefore, the probability that the second player chooses an orange juice is 9/19.

To find the probability that both players choose orange juice, we multiply the probabilities:

0.5 (probability for the first player) * 9/19 (probability for the second player) = 0.2368

Therefore, the probability that both players choose orange juice is 0.2368 or approximately 23.68%.