A Cook wants to cover the side of a cone Shaped funnel with parchment paper to avoid any leaks or spills. The funnel has a diameter of 6 inches in a slant height of four inches how many square inches Of parchment paper is needed to cover the side of the funnel? Use three point one four for Pi and round your number to the nearest hundredth

1 answer

To find the amount of parchment paper needed to cover the side of the cone-shaped funnel, we first need to calculate the lateral surface area of the cone. The formula for the lateral surface area \( A \) of a cone is given by:

\[ A = \pi r l \]

where \( r \) is the radius of the base of the cone, \( l \) is the slant height of the cone, and \( \pi \) is approximately 3.14.

Given that the diameter of the funnel is 6 inches, we can calculate the radius:

\[ r = \frac{\text{diameter}}{2} = \frac{6}{2} = 3 \text{ inches} \]

The slant height \( l \) is given as 4 inches. Now, we can substitute the values for \( r \) and \( l \) into the formula:

\[ A = \pi r l = 3.14 \times 3 \times 4 \]

Calculating the area:

\[ A = 3.14 \times 3 \times 4 = 3.14 \times 12 = 37.68 \text{ square inches} \]

Thus, the amount of parchment paper needed to cover the side of the funnel is

\[ \boxed{37.68} \text{ square inches.} \]