To find the distance the supplies travel from one end of the conveyor belt to the other, we can use trigonometry. The vertical change in height is 24 feet, and the angle of inclination is 60°. We can use the sine function to find the horizontal distance traveled:
sin(60°) = opposite/hypotenuse
sin(60°) = 24/x
x = 24/sin(60°)
x ≈ 27.7 feet
Therefore, the supplies travel approximately 28 feet from one end of the conveyor belt to the other.
Next, to find the time it takes for the supplies to move to the second floor, we can use the formula:
time = distance/speed
time = 28 ft / 75 ft/min
time ≈ 0.37 min
Rounded to the nearest tenth of a minute, it takes approximately 0.4 minutes (0.37 min) for the supplies to move to the second floor.
Therefore, the answer is:
• 28 ft; 0.4 min.
A conveyor belt carries supplies from the first floor to the second floor, which is 24 feet higher. The belt makes a 60° angle with the ground. How far do the supplies travel from one end of the conveyor belt to the other to the nearest foot? If the belt moves at 75 ft./min., how long does it take the supplies to move to the second floor to the nearest tenth of a minute?
(1 point)
• 34 1t.; 21.0 min.
• 42 it; 35.0 min.
• 14 fL; 1.0 min.
• 28 mt: 0,4 min.
1 answer