Di/Do = -1/4 is the magnification
(The - sign is there because it is a convex mirror with a virtual image.)
1/Do + 1/Di = -1/f = -1/19
1/Do -4/Do = -3/Do = -1/19
Do = 57 cm
Di = -Do/4 = -14.25 cm (behind the mirror)
A convex mirror has a focal length of 19.0 cm. Determine the object location for which the image will be one-fourth as tall as the object.
i really need help on this one. im completely stuck!
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